MHT CET202411 May 2024Morning ShiftMathematicsDifferentiationActual
If x^2+y^2= t + 1 t , x^4+y^4= t ^2+ 1 t ^2 , then d y ~d x =
Options
- A1 x^3 y
- B1 x y^3
- C- 1 x y^3
- D- 1 x^3 y
Correct answer
D. - 1 x^3 y
Step-by-step solution
array ll & x^2+y^2= t + 1 t and x^4+y^4= t ^2+ 1 t ^2 & (x^2+y^2 )^2= ( t + 1 t )^2 & x^4+y^4+2 x^2 y^2= t ^2+ 1 t ^2 +2 & t ^2+ 1 t ^2 +2 x^2 y^2= t ^2+ 1 t ^2 +2 & x^2 y ^2=1 & y^2= 1 x^2 array Differentiating w.r.t. x , we get aligned & 2 y ~d y ~d x = -2 x^3 & ~d y ~d x = -1 x^3 y aligned