MHT CET202310 May 2023Evening ShiftMathematicsDifferentiationActual
The displacement ' S ' of a moving particle at a time t is given by S=5+ 48 t +t^3 . Then its acceleration when the velocity is zero, is
Options
- A12
- B20
- C16
- D24
Correct answer
D. 24
Step-by-step solution
Given, S=5+ 48 t +t^3 Velocity (V)= d S d t =0- 48 t^2 +3 t^2 aligned & V= -48 t^2 +3 t^2 ...(i) & But V=0 ...[Given] & -48 t^2 +3 t^2=0 & t=2 aligned Now, A = dV dt aligned & = d d t ( -48 t^2 +3 t^2 ) & = 96 t^3 +6 t aligned Acceleration at t =2 is 96 8 +12=24