MHT CET202210 Aug 2022Evening ShiftMathematicsDifferentiationActual
For x R, f(x)=| 2- x| and g(x)=f(f(x)) , then
Options
- Ag^ (0)=- ( 2)
- Bg is not differentiable at x=0 .
- Cg^ (0)= ( 2)
- Dg is differentiable at x=0 and g^ (0)=- ( 2) .
Correct answer
C. g^ (0)= ( 2)
Step-by-step solution
for x 0⁻g(x)= 2- ( 2- x) for x 0⁺g(x)= 2- ( 2- x) [as 2> 0 and x> x ] and g(x) is continuous at x=0 aligned & now g^ (x)=0- ( 2- x)(0- x) & g^ (0)= ( 2) aligned