MHT CET202210 Aug 2022Evening ShiftMathematicsDifferentiationActual
If x= ⁻¹ ( 1 1+t^2 ), y= ⁻¹ ( 1 1+t^2 ) , then d y ~d x is
Options
- A0
- Bt t
- C1
- Dt t
Correct answer
C. 1
Step-by-step solution
let t= , then aligned & x= ⁻¹ ( 1 1+ ^2 )= ⁻¹ ( 1 )= ⁻¹ = & y= ⁻¹ ( 1+ ^2 )= ⁻¹ ( )= ⁻¹ = & d y d x = d( ) d =1 aligned