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MHT CET202123 Sep 2021Morning ShiftMathematicsDifferentiationActual

If y= ⁻¹ [ ( e x ^2 ) ( ex ^2 ) ]+ ⁻¹ [ 3+2 x 1-6 x ] , then d ^2 y dx ^2 =

Options

  1. A2 1+x^2
  2. B1 1+x^2
  3. C3 1+x^2
  4. D0

Correct answer

D. 0

Step-by-step solution

aligned & y= ⁻¹ [ ( e x ^2 ) ( ex ^2 ) ]+ ⁻¹ [ 3+2 x 1-6 x ] & = ⁻¹ [ e - x ^2 e + x ^2 ]+ ⁻¹ 3+ ⁻¹(2 x ) & = ⁻¹ [ 1- x ^2 1+ x ^2 ]+ ⁻¹ 3+ ⁻¹ ( x ^2 ) & = ⁻¹(1)- ⁻¹ ( x ^2 )+ ⁻¹ 3+ ⁻¹ ( x ^2 ) & = ⁻¹(1)+ ⁻¹(3) & dy dx =0 d ^2 y dx ^2 =0 aligned

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