MHT CET202123 Sep 2021Morning ShiftMathematicsDifferentiationActual
If y= ⁻¹ [ ( e x ^2 ) ( ex ^2 ) ]+ ⁻¹ [ 3+2 x 1-6 x ] , then d ^2 y dx ^2 =
Options
- A2 1+x^2
- B1 1+x^2
- C3 1+x^2
- D0
Correct answer
D. 0
Step-by-step solution
aligned & y= ⁻¹ [ ( e x ^2 ) ( ex ^2 ) ]+ ⁻¹ [ 3+2 x 1-6 x ] & = ⁻¹ [ e - x ^2 e + x ^2 ]+ ⁻¹ 3+ ⁻¹(2 x ) & = ⁻¹ [ 1- x ^2 1+ x ^2 ]+ ⁻¹ 3+ ⁻¹ ( x ^2 ) & = ⁻¹(1)- ⁻¹ ( x ^2 )+ ⁻¹ 3+ ⁻¹ ( x ^2 ) & = ⁻¹(1)+ ⁻¹(3) & dy dx =0 d ^2 y dx ^2 =0 aligned