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MHT CET202020 Oct 2020Evening ShiftMathematicsDifferentiationActual

If y=x^ x e^ x , d y d x =y g(x) , then g(x)=

Options

  1. A[e^ x +e^ x (x+1) x ]
  2. B[e^ x -e^ x x (1+ x) ]
  3. C[e^ x +e^ x x (1+ x) ]
  4. D[e^ x (x+1) x ]

Correct answer

A. [e^ x +e^ x (x+1) x ]

Step-by-step solution

We have y=x^ x e^ x y=x e^ x x 1 y d y d x =e^ x x+ x e^ x x +x e^ x x=e^ x x+e^ x +x e^ x x d y d x =y [e^ x +e^ x x(1+x) ]

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