MHT CET202019 Oct 2020Morning ShiftMathematicsDifferentiationActual
If x²+y²=t+ 1 t , x⁴+y⁴=t²+ 1 t² then d y d x =
Options
- A- y x
- By x
- Cx 2 y
- D- x 2 y
Correct answer
A. - y x
Step-by-step solution
(A) We have, x²+y²=t+ 1 t (1) and x⁴+y⁴=t²+ 1 t² ...(2) Squaring (1), we get array l x⁴+y⁴+2 x² y²=t²+ 1 t² +2 x⁴+y⁴+2 x² y²=x⁴+y⁴+2 ..(from (2)) x² y²=1 array Differentiating w.r.t. x , we get aligned & x² (2 y d y d x )+y²(2 x)=0 & d y d x = -2 x y² 2 x² y = -y x aligned