If x 1+x + y 1+y =0, x y , then d y d x =0

Step-by-step solution

(B) array l x 1+x + y 1+y =0 x ( 1+y )+y( 1+x )=0 x 1+y =-y 1+x array Squaring both sides we get, array l x²(1+y)=y²(1+x) x²+x² y=y²+x y² x²-y²=x y²-x² y (x-y)(x+y)=-x y(x-y) x+y=-x y (1+x) y=-x y= -x 1+x array Differentiating both sides w.r.t. x , we get aligned & d y d x =- (1+x)(1)-(x)(1) (1+x)² = -1 (1+x)² &(1+x)² d y d x =-1 aligned