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AP EAMCET202124 Aug 2021Evening ShiftMathematicsApplication of DerivativesActual

The point on the curve x^2+y^2=a^2, y 0 , at which the tangent is parallel to the x -axis is

Options

  1. A(a, 0)
  2. B(-a, 0)
  3. C(0, a)
  4. D(0,-a)

Correct answer

C. (0, a)

Step-by-step solution

We have, x^2+y^2=a^2 2 x+2 y d y d x =0 d y d x = -x y Tangent is parallel to X -axis. d y d x =0 -x y =0 ; x=0 Putting the value of x in x^2+y^2=a^2 0+y^2=a^2 y=a, y 0 The point on the curve is (0, a) .

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