If x = a sin - 1 ⁡ t , y = a cos - 1 ⁡ t , then d y d x = ………

Step-by-step solution

If x = a s i n - 1 t y = a c o s - 1 t Then, s i n - 1 t = l o g a x 2 and c o s - 1 t = l o g a y 2 Then, 2 l o g e a l o g e x + l o g e y = π 2 Differentiate both sides w.r.t. x We get, 1 x + 1 y d y d x = a ⇒ d y d x = - y x