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MHT CET2011MathematicsDifferentiation

If x^ p y^ q =(x+y)^ p+q , then d y d x is equal to

Options

  1. Ay / x
  2. Bp y / q x
  3. Cx / y
  4. Dq y / p x

Correct answer

A. y / x

Step-by-step solution

Given, x^ p y^ q =(x+y)^ p+q Taking log on both sides, we get array l p x+q y=(p+q) (x+y) p x + q y d y d x = (p+q) (x+y) (1+ d y d x ) ( p x - p+q x+y )= ( p+q x+y - q y ) d y d x d y d x = y x array

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