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MHT CET2011MathematicsDifferentiation

If x=2 t- 2 t, y=2 t- 2 t , then the value of . d² y d x² |_ t= / 2 is

Options

  1. A3 / 2
  2. B5 / 2
  3. C5 / 2
  4. D-3 / 2

Correct answer

D. -3 / 2

Step-by-step solution

d x d t =-2 t+2 2 t aligned d y d t &=2 t-2 2 t d y d x &= 2 t-2 2 t -2 t+2 2 t &= t- 2 t 2 t- t &= 2 3 t 2 t 2 2 3 t 2 t 2 &= 3 t 2 aligned aligned d² y d x² &= ² 3 t 2 3 2 d t d x &= 3 2 ² 3 t 2 1 (2 2 t-2 t) & . d² y d x² |_ t= / 2 =-3 / 2 aligned

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