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MHT CET2011MathematicsDifferentiation

A particle moves along a straight line according to the law s=16-2 t+3 t³ , where s metres is the distance of the particle from a fixed point at the end of t second. The acceleration of the particle at the end of 2 ~s is

Options

  1. A3.6 ~m / s ²
  2. B36 ~m / s ²
  3. C36 ~km / s ²
  4. D360 ~m / s ²

Correct answer

B. 36 ~m / s ²

Step-by-step solution

Given, s=16-2 t+3 t³ array lc & d s d t =-2+9 t² d² s d t² =18 t array Now, the acceleration of the particle at the end of t=2 ~s is f= d² s d t² =18 2=36 ~m / s ²

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