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MHT CET2009MathematicsDifferentiation

The value of ( ² E ) x³ at h=1 is

Options

  1. A8 x
  2. B6 x
  3. C5 x²
  4. D6 x²

Correct answer

B. 6 x

Step-by-step solution

aligned & ( ² E ) x³= ( (E-1)² E ) x³ &= ( E²-2 E+1 E ) x³ &=E (x³ )-2 x³+E⁻¹ (x³ ) &=(x+1)³-2 x³+(x-1)³ &=x³+1+3 x²+3 x-2 x³+x³-1-3 x²+3 x &=6 x aligned

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