MHT CET2007MathematicsDifferentiation
The derivative of |x| is
Options
- A1 x , x>0
- B1 |x| , x 0
- C1 x , x 0
- DNone of these
Correct answer
C. 1 x , x 0
Step-by-step solution
We have, y= |x|= array ll x & , x>0 (-x), & x 0 1 -x (-1)= 1 x , & x < 0 array . d y d x = 1 x , x 0 array