MHT CET202620 April 2026Morning ShiftMathematicsEllipseActual
If is the eccentric angle of a point on the ellipse x^2 25 + y^2 9 = 1 such that the distance of the point from the center is 5 , then = .......
Options
- A0
- B6
- C3
- D2
Correct answer
A. 0
Step-by-step solution
The equation of the ellipse is x^2 25 + y^2 9 = 1 Let the point on the ellipse be P(5 , 3 ) The distance of P from the center (0,0) is given as 5 (5 )^2 + (3 )^2 = 5 Squaring both sides: 25 ^2 + 9 ^2 = 25 25 ^2 + 9(1 - ^2 ) = 25 16 ^2 + 9 = 25 16 ^2 = 16 ^2 = 1 = 1 = 0 or From the given options, = 0 Answer: 0