AP EAMCET202123 Aug 2021Evening ShiftMathematicsApplication of DerivativesActual
Find the coordinates of a point on the curve y=x^2-3 x+2 , at which the tangent drawn to this curve is perpendicular to the line y=x .
Options
- A(0,2)
- B(1,0)
- C(-1,6)
- D(2,-3)
Correct answer
B. (1,0)
Step-by-step solution
Given curve, y=x^2-3 x+2 On differentiating w.r.t. x , d y d x =2 x-3 Which represents the slope of tangent drawn to the curve. m₁=2 x-3 ...(i) Given line, y=x ...(ii) On comparing with y=m x+c Slope of line (ii), m₂=1 Tangent to the curve is perpendicular to line (ii). m₁ m₂=-1m₁ 1=-1 array cc & m₁=-1 & 2 x-3=-1 & 2 x=2 & x=1 array y=(1)^2-3 1+2y=0 Point of tangent drawn =(1,0)