MHT CET202312 May 2023Evening ShiftMathematicsFunctionsActual
If f (x)=x^2+1 and g (x)= 1 x , then the value of f ( g ( g ( f (x)))) at x=1 is
Options
- A4
- B1
- C5
- D3
Correct answer
C. 5
Step-by-step solution
aligned f (x)=x^2+1, & ~g (x)= 1 x f ( g ( g ( f (x)))) & = f ( g ( g (x^2+1 ) ) ) & = f ( g ( 1 x^2+1 ) ) & = f (x^2+1 ) & = (x^2+1 )^2+1 aligned At x=1 , we get the value of above function aligned & = [(1)^2+1 ]^2+1 & =5 aligned