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MHT CET202312 May 2023Evening ShiftMathematicsFunctionsActual

If f (x)=x^2+1 and g (x)= 1 x , then the value of f ( g ( g ( f (x)))) at x=1 is

Options

  1. A4
  2. B1
  3. C5
  4. D3

Correct answer

C. 5

Step-by-step solution

aligned f (x)=x^2+1, & ~g (x)= 1 x f ( g ( g ( f (x)))) & = f ( g ( g (x^2+1 ) ) ) & = f ( g ( 1 x^2+1 ) ) & = f (x^2+1 ) & = (x^2+1 )^2+1 aligned At x=1 , we get the value of above function aligned & = [(1)^2+1 ]^2+1 & =5 aligned

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