Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET20226 Aug 2022Morning ShiftMathematicsFunctionsActual

For a suitable chosen real constant a , let a function f: R-[-a] R be defined by f(x)= a-x a+x . Further, suppose that for any real number x -a and f(x) -a,(f o f)(x)=x . Then f ( -1 2 ) is equal to

Options

  1. A-1 3
  2. B3
  3. C1 3
  4. D-3

Correct answer

B. 3

Step-by-step solution

aligned & (f f)(x)= a- a-x a+x a+ a-x a+x =x & a^2+a x-a+x a^2+a x+a-x =x & (a+1) x+ (a^2-a )= (a^2+a ) x+(a-1) x^2 & a+1=a^2+a, a^2-a=0, a-1=0 & a=1 & f(x)= 1-x 1+x & f (- 1 2 )= 1+ 1 2 1- 1 2 =3 aligned

Practice Functions on Quantrex Academy →

More from Functions

If f : R A , defined by f ( x )= x + 3 x -1 , is an onto function then A = 2025Let g(x)=1+x-[x] and f(x)= cases -1, & x 0 cases ([x] ) denotes the greatest integer less than or equal to (x ). Then for all x , f ( g ( x ))= 2025The domain of the real valued function f(x)= 3 4-x^2 + ₁₀ (x^3-x ) is 2025A real valued function f: A B defined by f(x)= 4-x^2 4+x^2 x A is a bijection. If -4 A then A B= 2025Let [ x ] represent the greatest integer less than or equal to x , x = x -[ x ] , 2 =1.414 and 3 =1.732 . If f(x)= x+ [ x 1+x^2 ] is a real valued function, then f ( 2 )+ f (- 3 )= 2025If the range of the function f(x)=-3 x-3 is 3,-6,-9,-18 , then which one of the following is not in the domain of f ? 2025The domain of the function f(x)= _e ( 1 x^2-4 x+4 ) + ⁻¹ (x^2-2 ) is 2025Consider the following statements Statement-I : A function f : A B is said to be one-one if and only if f(x) f(y) x y Statement-II : A relation f: A B is said to be a function if x 2025 Full Functions list All MHT CET PYQs