MHT CET202120 Sep 2021Morning ShiftMathematicsFunctionsActual
If f ( x )=[ x ] , for x (-1,2) , then f is discontinuous at (where [ x ] represents floor function)
Options
- Ax =-1,0,1,2
- Bx =-1,0,1
- Cx =0,1
- Dx =2
Correct answer
C. x =0,1
Step-by-step solution
We have f ( x )=[ x ] Let [ x ]= K , an integer. _ x K⁺ f(x)=K and _ x K⁻ f(x)=K-1 Thus given function is not continuous at all integral values in its domain. f is discontinuous at x =0,1 .