If D₃₀ is the set of all divisors of 30, x, y D₃₀ , we define x+y= LCM (x, y), x y= GCD (x, y) , x^ = 30 x and f(x, y, z)=(x+y) (y^ +z ) , then f(2,5,15) is equal to

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Correct answer: C. 10

D₃₀= 1,2,3,5,6,10,15,30 aligned f(2,5,15) &=(2+5) (5^ +15 ) &=10 ( 30 5 +15 ) &=10(6+15) &=10 30 &=10 aligned

If D₃₀ is the set of all divisors of 30, x, y D₃₀ , we define x+y= LCM (x, y), x y= GCD (x, y) , x^ = 30 x and f(x, y, z)=(x+y) (y^ +z ) , then f(2,5,15) is equal to

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