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MHT CET202620 April 2026Morning ShiftMathematicsIndefinite IntegrationActual

x^4(x¹⁰ - 1) x²⁰ + 3x¹⁰ + 1 , dx =

Options

  1. A⁻¹ (x^5 + 1 x^5 ) + c
  2. B1 5 ⁻¹ (x^5 + 1 x^5 ) + c
  3. C⁻¹ (x¹⁰ + 1 x¹⁰ ) + c
  4. D1 10 ⁻¹ (x¹⁰ + 1 x¹⁰ ) + c

Correct answer

B. 1 5 ⁻¹ (x^5 + 1 x^5 ) + c

Step-by-step solution

I = x^4(x¹⁰ - 1) x²⁰ + 3x¹⁰ + 1 , dx Dividing the numerator and the denominator by x¹⁰ : I = x^4 - 1 x^6 x¹⁰ + 3 + 1 x¹⁰ , dx Let x^5 + 1 x^5 = t Differentiating with respect to x : (5x^4 - 5 x^6 ) dx = dt (x^4 - 1 x^6 ) dx = dt 5 The denominator can be written as: x¹⁰ + 1 x¹⁰ + 3 = (x^5 + 1 x^5 )^2 - 2 + 3 = t^2 + 1 Substituting these into the integral: I = 1 t^2 + 1 dt 5 I = 1 5 ⁻¹(t) + c I = 1 5 ⁻¹ (x^5 + 1 x^5 ) + c Answer: 1 5 ⁻¹ (x^5 + 1 x^5 ) + c

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