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MHT CET202611 April 2026Evening ShiftMathematicsIndefinite IntegrationActual

2x 4 - 3x - x^2 dx =

Options

  1. A8 5 |4 + x| - 2 5 |1 - x| + c
  2. B2 |4 + x| + 2 5 |1 - x| + c
  3. C- |4 + x| + 2 5 |1 - x| + c
  4. D- 8 5 |4 + x| - 2 5 |1 - x| + c

Correct answer

D. - 8 5 |4 + x| - 2 5 |1 - x| + c

Step-by-step solution

Let I = 2x 4 - 3x - x^2 dx Factorizing the denominator: 4 - 3x - x^2 = (1 - x)(4 + x) Using partial fractions: 2x (1 - x)(4 + x) = A 1 - x + B 4 + x 2x = A(4 + x) + B(1 - x) Substituting x = 1 , we get 2 = 5A A = 2 5 Substituting x = -4 , we get -8 = 5B B = - 8 5 Therefore, I = ( 2/5 1 - x - 8/5 4 + x ) dx I = 2 5 ( |1 - x| -1 ) - 8 5 |4 + x| + c I = - 8 5 |4 + x| - 2 5 |1 - x| + c Answer: - 8 5 |4 + x| - 2 5 |1 - x| + c

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