Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET20255 May 2025Evening ShiftMathematicsIndefinite IntegrationActual

If A = [ array lll a & 0 & 0 0 & ~b & 0 0 & 0 & c array ] where a =7^ x , b =7^ 7^x , c =7^ 7^ 7^x then |A| d x , (Where |A| is the determinant of the matrix A ) is equal to

Options

  1. A7^ 7^x ( 7)^3 +k, where k is constant of integration
  2. B7^ 7^ 7^x 7 + k , where k is constant of integration
  3. C7^ 7^ 7^x ( 7)^3 + k , where k is constant of integration
  4. D7^ 7^ 7^x ( 7)^3+ k , where k is constant of integration

Correct answer

C. 7^ 7^ 7^x ( 7)^3 + k , where k is constant of integration

Step-by-step solution

Determinant Evaluation: The determinant of the diagonal matrix A is the product of its diagonal elements: |A| = a b c = 7^x 7^ 7^x 7^ 7^ 7^x . Integral Setup: The required integral is |A| dx = 7^x 7^ 7^x 7^ 7^ 7^x dx . Substitution: Let u = 7^ 7^ 7^x . Differentiating using the chain rule: du dx = 7^ 7^ 7^x 7 d dx (7^ 7^x ) = 7^ 7^ 7^x 7 (7^ 7^x 7 7^x 7) = 7^ 7^ 7^x 7^ 7^x 7^x ( 7)^3 . This gives dx = du u 7^ 7^x 7^x ( 7)^3 . Integration: Substituting into the integral yields u du u ( 7)^3 = 1 ( 7)^3 du = u ( 7)^3

Practice Indefinite Integration on Quantrex Academy →

More from Indefinite Integration

If 5 x x -2 dx = ax + b | x -2 x |+ c , then a + b = 2025x Cos ⁻¹ ( 1-x^2 1+x^2 ) d x(x>0)= 2025d x (1+ x ) x-x^2 = 2025If x x x+1 ~d x= f (x)+ k , then f ( 4 )= 2025If x^4+1 x^2+1 d x=A x^3+B x^2+C x+D Tan ⁻¹ x+E , then A+B+C+D= 2025If x^2-x+2 x^2+x+2 d x=x- (f(x))+ 2 7 Tan ⁻¹(g(x))+c , then f (-1)+ 7 ~g (-1)= 2025(x- 3 ) (x+ 6 ) d x= 2025If a x+3 x 5 x+2 x d x= 26 29 x- k 29 |5 x+2 x|+c , then |a+k|= 2025 Full Indefinite Integration list All MHT CET PYQs