Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202520 Apr 2025Evening ShiftMathematicsIndefinite IntegrationActual

e^x (x-1) (x+1)^3 ~d x=

Options

  1. Ae ^x(x+1)^2+ c , where c is the constant of integration
  2. Be ^x(x+1)^3+ c , where c is the constant of integration
  3. Ce ^x (x+1)^2 + c , where c is the constant of integration
  4. De ^x (x+1)^3 + c , where c is the constant of integration

Correct answer

C. e ^x (x+1)^2 + c , where c is the constant of integration

Step-by-step solution

Evaluate the integral e^x x-1 (x+1)^3 d x using the standard formula e^x [f(x) + f'(x)] d x = e^x f(x) + C . Express the integrand in the appropriate form by rewriting the numerator: x-1 (x+1)^3 = (x+1) - 2 (x+1)^3 = 1 (x+1)^2 - 2 (x+1)^3 Let f(x) = 1 (x+1)^2 Then f'(x) = - 2 (x+1)^3 Thus the integrand becomes f(x) + f'(x) Applying the formula yields: e^x [ 1 (x+1)^2 - 2 (x+1)^3 ] d x = e^x 1 (x+1)^2 + C = e^x (x+1)^2 + C This corresponds to option C .

Practice Indefinite Integration on Quantrex Academy →

More from Indefinite Integration

If 5 x x -2 dx = ax + b | x -2 x |+ c , then a + b = 2025x Cos ⁻¹ ( 1-x^2 1+x^2 ) d x(x>0)= 2025d x (1+ x ) x-x^2 = 2025If x x x+1 ~d x= f (x)+ k , then f ( 4 )= 2025If x^4+1 x^2+1 d x=A x^3+B x^2+C x+D Tan ⁻¹ x+E , then A+B+C+D= 2025If x^2-x+2 x^2+x+2 d x=x- (f(x))+ 2 7 Tan ⁻¹(g(x))+c , then f (-1)+ 7 ~g (-1)= 2025(x- 3 ) (x+ 6 ) d x= 2025If a x+3 x 5 x+2 x d x= 26 29 x- k 29 |5 x+2 x|+c , then |a+k|= 2025 Full Indefinite Integration list All MHT CET PYQs