MHT CET20243 May 2024Evening ShiftMathematicsIndefinite IntegrationActual
If f ( x-4 x-2 )=2 x+1, x R - 1,-2 , then f (x) d x is equal to
Options
- A5 x-4 (x-1)+ c , where c is constant of integration.
- Bx-4 (x-1)+c , where c is constant of integration.
- C5 x+4 (x-1)+ c , where c is constant of integration.
- D5 x+ (x-1)+ c , where c is constant of integration.
Correct answer
A. 5 x-4 (x-1)+ c , where c is constant of integration.
Step-by-step solution
aligned & f ( x-4 x-2 )=2 x+1 & Let x-4 x-2 =y & x-2-2 x-2 =y & 1- 2 x-2 =y & -2 x-2 =y-1 & -2 y-1 =x-2 & x= -2 y-1 +2 & 2 x= -4 y-1 +4 & 2 x+1= -4 y-1 +5 aligned aligned & f (y)= -4 y-1 +5 & f (x)= -4 x-1 +5 & f (x) d x= -4 x-1 +5 & =-4 (x-1)+5 x+c & =5 x-4 (x-1)+c aligned