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AP EAMCET202023 Sep 2020Morning ShiftMathematicsApplication of DerivativesActual

The tangent to the curve y = e 2 x at the point 0 , 1 meets the x -axis at

Options

  1. A2 ,   0
  2. B0 ,   0
  3. C- 1 2 ,   0
  4. D1 2 ,   0

Correct answer

C. - 1 2 ,   0

Step-by-step solution

The tangent to the curve y = 2 2 x at the pts ( 0 , 1 ) meets the x - a x i e s ⇒ y = e 2 x d y d x = 2 e 2 x d y d x ( 0 , 1 ) = 2 e 2 ( 0 ) = 2 e q n of tangent ( y - y 1 ) = d y d x ( x - x 1 ) ( y - 1 ) = 2 ( x - 0 ) y = 2 x + 1 meets the x-axies y = 0 2 x + 1 = 0 x = - 1 2 = ( - 1 2 , 0 )

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