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AP EAMCET202022 Sep 2020Evening ShiftMathematicsApplication of DerivativesActual

Tangent at any point on the curve x=35 y=35 is

Options

  1. Ay =x+35
  2. By =x-35
  3. Cy =x-35
  4. Dy =x+35

Correct answer

B. y =x-35

Step-by-step solution

Given, x=35 gathered y=35 Point P=(35 , 35 ) Differentiate Eq. (i) w.r.to ' ' d x d =35( ) gathered d x d =35( ) Differentiate Eq. (ii) w.r.to ' ' aligned d y d & =35 ( ^2 ) Eq. (iv) Eq. (iii) d y d x & = 35 ( ^2 ) 35( ) d y d x & = = 1 aligned m= 1 Equation of tangent is aligned y-35 & =m(x-35 ) y-35 & = 1 (x-35 1 ) y -35 ^2 & =x- 35 y & =x+ 35 ^2 - 35 y & =x+ 35 ( ^2 -1 ) y & =x+ 35(- 2 ) y & =x-35 aligned Hence, option (2) is correct.

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