AP EAMCET202021 Sep 2020Evening ShiftMathematicsApplication of DerivativesActual
The curve (y=a x^3+b x^2+c x+5 ) touches the (X )-axis at (P(-2,0) ) and cuts (Y )-axis at a point (Q ), where gradient is 3 . Then the values of (a, b, c ) are
Options
- A(a= -1 2 , b= -3 4 , c=3 )
- B(a= 1 2 , b= 3 4 , c=3 )
- C(a=1, b=2, c=3 )
- D(a=-1, b=-2, c=3 )
Correct answer
A. (a= -1 2 , b= -3 4 , c=3 )
Step-by-step solution
The equation of given curve is (y=a x^3+b x^2+c x+5 ) ...(i) ( ) Curve (i) passes through point (P(-2,0) ), so (-8 a+4 b-2 c+5=0 ) ...(ii) and curve (i) cuts the (Y )-axis at a point (Q ) with gradient 3, so ( . d y d x |_Q=3 ) ( 3 a x^2+2 b x+ .c |_ x=0 c=3 ) ...(iii) ( ) Point (Q ) have coordinates ((0,5) ), so curve (i) passes through (Q(0,5) ). From Eqs. (ii) and (iii), we have (8 a-4 b+1=0 ). Now, from the options (c=3, a=- 1 2 and b=- 3 4 ) Hence, option (a) is correct.