Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET2016MathematicsIndefinite Integration

∫ 4 e x - 25 2 e x - 5 d x = A x + B log ⁡ | 2 e x - 5 | + c then

Options

  1. AA = 5 , B = 3
  2. BA = 5 , B = - 3
  3. CA = - 5 , B = 3
  4. DA = - 5 , B = - 3

Correct answer

B. A = 5 , B = - 3

Step-by-step solution

Let I = 4 e x - 25 2 e x - 5 d x ⇒ I = ∫ 10 e x - 25 - 6 e x 2 e x - 5 d x ⇒ I = ∫ 5 2 e x - 5 - 6 e x 2 e x - 5 d x ⇒ I = ∫ 5 - 6 e x 2 e x - 5 d x ⇒ I = 5 x - 3 log ⁡ 2 e x - 5 + C ∴ A = 5 a n d B = - 3

Practice Indefinite Integration on Quantrex Academy →

More from Indefinite Integration

If 5 x x -2 dx = ax + b | x -2 x |+ c , then a + b = 2025x Cos ⁻¹ ( 1-x^2 1+x^2 ) d x(x>0)= 2025d x (1+ x ) x-x^2 = 2025If x x x+1 ~d x= f (x)+ k , then f ( 4 )= 2025If x^4+1 x^2+1 d x=A x^3+B x^2+C x+D Tan ⁻¹ x+E , then A+B+C+D= 2025If x^2-x+2 x^2+x+2 d x=x- (f(x))+ 2 7 Tan ⁻¹(g(x))+c , then f (-1)+ 7 ~g (-1)= 2025(x- 3 ) (x+ 6 ) d x= 2025If a x+3 x 5 x+2 x d x= 26 29 x- k 29 |5 x+2 x|+c , then |a+k|= 2025 Full Indefinite Integration list All MHT CET PYQs