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AP EAMCET202017 Sep 2020Evening ShiftMathematicsApplication of DerivativesActual

The equation of tangent to the curve (y=5 x^2-3 x+7 ) at the point ((-1,4) ) is ......

Options

  1. A(13 x-y-9=0 )
  2. B(13 x+y-9=0 )
  3. C(13 x+y+9=0 )
  4. D(13 x+2 y+5=0 )

Correct answer

C. (13 x+y+9=0 )

Step-by-step solution

Curve is, (y=5 x^2-3 x+7 ) Slope of tangent to curve at ((-1,4) ) is, (m_T= . d y d x |_ (-1,4) = .(10 x-3) |_ x=-1 =-13 ) Equation of tangent is, ( aligned & y-y₁=m_T (x-x₁ ) & y-4=-13(x+1) & 13 x+y+9=0 aligned )

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