AP EAMCET202017 Sep 2020Evening ShiftMathematicsApplication of DerivativesActual
A kind of bacteria grows by (t^3 ) in (t ~s ). Time taken for the rate of growth of the bacteria to become 1200 per (s ) is
Options
- A(10 ~s )
- B(20 ~s )
- C(40 ~s )
- D(400 ~s )
Correct answer
B. (20 ~s )
Step-by-step solution
Given, ( d N d t =t^3, ) When, rate of growth is 1200 we have, ( aligned & d d t ( d N d t )=1200 d d t t^3=1200 & 3 t^2=1200 t^2=400 & t=20 sec aligned )