MHT CET202519 Apr 2025Morning ShiftMathematicsInverse Trigonometric FunctionsActual
The derivative of ⁻¹ ( 1+x^2 -1 ) is
Options
- Ax 1+x^2 (x^2-2 x+1 +1 )
- Bx 1+x^2 (x^2-2 1+x^2 +3 )
- Cx 1+x^2 (x^2-2 x^2+1 +2 )
- Dx 1+x^2 (x^2+2 1+x^2 -3 )
Correct answer
B. x 1+x^2 (x^2-2 1+x^2 +3 )
Step-by-step solution
Derivative of ( d d x [ ⁻¹ ( 1+x^2 -1 ) ] ) Let (u= 1+x^2 -1 . ) Then ( d d x ⁻¹(u)= u^ 1+u^2 ) We have (u^ = x 1+x^2 ) and (1+u^2=1+ ( 1+x^2 -1 )^2=x^2+3-2 1+x^2 . ) Thus the derivative equals ( x 1+x^2 (x^2-2 1+x^2 +3 ) )