Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET20242 May 2024Morning ShiftMathematicsInverse Trigonometric FunctionsActual

The number of real solutions of ⁻¹ x(x+1) + ⁻¹ x^2+x+1 = 2 is

Options

  1. Azero.
  2. Bone.
  3. Ctwo.
  4. Dinfinite.

Correct answer

C. two.

Step-by-step solution

⁻¹ x(x+1) + ⁻¹ x^2+x+1 = 2 ⁻¹ x(x+1) is defined when x(x+1) 0 ⁻¹ x^2+x+1 is defined when x(x+1)+1 1 or x(x+1) 0 From (i) and (ii), x(x+1)=0 or x=0 and -1 . Hence, number of solutions is 2 .

Practice Inverse Trigonometric Functions on Quantrex Academy →

More from Inverse Trigonometric Functions

If y = ⁻¹ ( 1+x^3 + 1-x^3 1+x^3 - 1-x^3 ) then dy dx = 2026If X = ⁻¹ [2 (2 ⁻¹ 1 2 ) ] + ⁻¹ [ ( 7 6 ) ] and Y = ⁻¹ [ ( 11 6 ) ] + ⁻¹ [ ( 4 3 ) ] then the value of 2X - Y is: 2026The value of the expression ⁻¹ ( 7 6 ) + ⁻¹ ( 22 3 ) + ⁻¹ ( 4 5 ) is: 2026Which of the following is the simplest form of the expression ⁻¹ ( 1+x^2 - 1 x ) where x 0 2026If ⁻¹ x + ⁻¹ y = 2 , then x^2 is equal to 2026⁻¹ ( 1 1 + 1 2 ) + ⁻¹ ( 1 1 + 2 3 ) + + ⁻¹ ( 1 1 + n(n+1) ) = 2026The second order derivative of ⁻¹(4x^3 - 3x) with respect to ⁻¹(2x^2 - 1) , where 1 2 < x < 1 is 2026If 2 ⁻¹x - 3 ⁻¹x = 4 , then 2 ⁻¹x + 3 ⁻¹x = 2026 Full Inverse Trigonometric Functions list All MHT CET PYQs