Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET202415 May 2024Evening ShiftMathematicsLimitsActual

_ x 2 3^x+3^ 3-x -12 3^ 3-x -3^ x 2 =

Options

  1. A- 4 3
  2. B4 3
  3. C2 3
  4. D- 4 9

Correct answer

A. - 4 3

Step-by-step solution

aligned & _ x 2 3^x+3^ 3-x -12 3^ 3-x -3^ x 2 & = _ x 2 (3^x )^2+3^3-12 (3^x ) 3^3- (3^ x 2 )^3 & = _ x 2 (3^x-9 ) (3^x-3 ) (3-3^ x 2 ) (9+3.3^ x 2 +3^x ) & =- _ x 2 (3^ x 2 +3 ) (3^ x 2 -3 ) (3^x-3 ) (3^ x 2 -3 ) (3^x+3.3^ x 2 +9 ) & =- (3+3)(9-3) 9+9+9 aligned = -4 3

Practice Limits on Quantrex Academy →

More from Limits

If _ x 0 ( p 2x + 1 - 2x x + x ) = 1 then the value of ' p ' is 2026_ x 2 ( 1 - x x ) is equal to 2026The value of _ x 3 [ 1 x-3 + 9x 27-x^3 ] is: 2026_ x 0 (1 - 2x)(3 + x) x 4x is equal to: 2026If _ x 3 ( x^2 - ax - 3b x - 3 ) = 5 , then a + b = 2026If f(x) = cases x^2 - 1 & if x 2 x + 1 & if x < 2 cases , then _ x 1 f(x) + _ x 2 f(x) = 2026_ x 4 2 2 -( x+ x)^3 1- 2 x = 2025Let [x] denote the greatest integer less than or equal to x . Then _ x 2⁺ ( [x]^3 3 - [ x 3 ]^3 )= 2025 Full Limits list All MHT CET PYQs