Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
MHT CET20242 May 2024Morning ShiftMathematicsLimitsActual

If f (x)= 1+ x (1-x)^2 , for x 1 is continuous at x=1 , then f (1) is equal to

Options

  1. A2
  2. B2
  3. C^2 4
  4. D4 ^2

Correct answer

A. 2

Step-by-step solution

aligned f (x) & = 1+ x (1-x)^2 f (1) & = _ x 1 f (x) & = _ x 1 1+ x (1-x)^2 aligned aligned & Put 1-x= h & 1- h =x & As x 1, ~h 0 & aligned f (1) & = _ h 0 1+ (1- h ) h ^2 = & _ h 0 1+ ( - h) h ^2 = & _ h 0 1- h h ^2 = & _ h 0 2 ^2 ~h 2 ~h ^2 = & 2 _ h 0 ^2 h 2 ^2 h^2 4 4 = & 2 4 _ h 0 ( h 2 h 2 )^2 f (1) & = 2 aligned aligned

Practice Limits on Quantrex Academy →

More from Limits

If _ x 0 ( p 2x + 1 - 2x x + x ) = 1 then the value of ' p ' is 2026_ x 2 ( 1 - x x ) is equal to 2026The value of _ x 3 [ 1 x-3 + 9x 27-x^3 ] is: 2026_ x 0 (1 - 2x)(3 + x) x 4x is equal to: 2026If _ x 3 ( x^2 - ax - 3b x - 3 ) = 5 , then a + b = 2026If f(x) = cases x^2 - 1 & if x 2 x + 1 & if x < 2 cases , then _ x 1 f(x) + _ x 2 f(x) = 2026_ x 4 2 2 -( x+ x)^3 1- 2 x = 2025Let [x] denote the greatest integer less than or equal to x . Then _ x 2⁺ ( [x]^3 3 - [ x 3 ]^3 )= 2025 Full Limits list All MHT CET PYQs