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MHT CET202124 Sep 2021Evening ShiftMathematicsLimitsActual

_ x 0 1- x^2 1- x =

Options

  1. A2
  2. B1 2
  3. C0
  4. D1 2

Correct answer

A. 2

Step-by-step solution

aligned & _ x 0 1- x^2 1- x & = _ x 0 2 ^2 x^2 2 2 ^2 x 2 = _ x 0 2 x^2 2 2 ^2 x 2 aligned Dividing numerator and denominator by x^2 4 , we get 1 2 _ x 0 [ ( x^2 2 ) ( x^2 4 ) ] ( x 2 ) ( x 2 ) 1 2 _ x 0 ( x^2 2 ) ( x 2 ) = .x^2 ) 1 2 [ x 2 ) = 1 2 2 1 = 2

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