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MHT CET202122 Sep 2021Evening ShiftMathematicsLimitsActual

_ x 2 (x-1)^ 1 3 x-6 =

Options

  1. Ae ^2
  2. Be ^3
  3. Ce ^ 1 3
  4. De ^ 1 2

Correct answer

C. e ^ 1 3

Step-by-step solution

aligned & _ x 2 (x-1)^ 1 3 x-6 & = _ x 2 (x-2+1)^ 1 3(x-2) = _ x 2 [1+(x-2)]^ 1 (x-2) ^ 1 3 =e^ 1 3 aligned

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