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AP EAMCET201920 Apr 2019Morning ShiftMathematicsApplication of DerivativesActual

The time (T ) of oscillation of a simple pendulum of length (L ) is governed by (T=2 L g ), where (g ) is constant. The percentage by which the length be changed in order to correct an error of loss equal to 2 minutes of time per day is

Options

  1. A(- 5 18 )
  2. B(- 2 9 )
  3. C( 1 6 )
  4. D( 1 9 )

Correct answer

A. (- 5 18 )

Step-by-step solution

For simple pendulum of length (L ), the time of oscillation is ( aligned & T=2 L g T T 100= 1 2 L L & L L %=- 2 2 24 60 100( T=2 ~min ) & =- 10 36 = -5 18 aligned ) ( L L =- 5 18 ) percentage. Hence, option (1) is correct.

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