MHT CET20249 May 2024Evening ShiftMathematicsLinear ProgrammingActual
The maximum value of z =4 x+2 y , subject to the constraints 3 x+4 y 12, x+y 5, x, y 0 is
Options
- A8
- B20
- C24
- D16
Correct answer
B. 20
Step-by-step solution
The feasible region. lies on the origin side of x+y=5 and non-origin side of 3 x+4 y=12 , in the first quadrant. The corner points of the feasible region are A (4,0), B (5,0), C (0,5) and D (0,3) . z=4 x+2 y At A (4,0), z =16 At B(5, 0), z=20 At C(0, 5), z=10 At D(0,3), z=6 Maximum value of z is 20.