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MHT CET20239 May 2023Morning ShiftMathematicsLinear ProgrammingActual

If feasible region is as shown in the figure, then the related inequalities are

Options

  1. A3 x+4 y 12, y-x 0, y 3, x, y 0
  2. B3 x+4 y 12, y-x 0, y 3, x, y 0
  3. C3 x+4 y 12, y-x 0, y 3, x, y 0
  4. D3 x+4 y 12, y-x 0, y 3, x, y 0

Correct answer

A. 3 x+4 y 12, y-x 0, y 3, x, y 0

Step-by-step solution

The shaded region lies: on non-origin side of line 3 x+4 y=12 i.e., 3 x+4 y 12 , on the side of the line y-x=0 , where y x i.e., y-x 0 , on origin side of line y=3 i.e., y 3 , and in first quadrant i.e., x 0, y 0 .

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