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MHT CET202124 Sep 2021Morning ShiftMathematicsLinear ProgrammingActual

The minimum value of the objective function z=4 x+6 y subject to x+2 y 80,3 x+y 75, x, y 0 is

Options

  1. A324
  2. B250
  3. C320
  4. D254

Correct answer

D. 254

Step-by-step solution

Refer figure Required area is shaded. Vertices of feasible region are A =(80,0) ; C =(0,75) and point of intersection of given lines is B =(14,33) We have to minimize objective function z =4 x +6 y aligned & Z _ ( A ) =4(80)+6(0)=320 & Z _ ( B ) =4(14)+6(33)=254 & Z _ ( C ) =4(0)+6(75)=450 & aligned

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