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MHT CET202020 Oct 2020Morning ShiftMathematicsLinear ProgrammingActual

The minimum value of the objective function Z =5 x+8 y , subject to x+ y 5x 4, y 2, x 0, y 0 occur at the point

Options

  1. A(5,0)
  2. B(0,5)
  3. C(4,2)
  4. D(4,1)

Correct answer

D. (4,1)

Step-by-step solution

Feasible area is shaded. Vertices of the feasible region are A (4,1), B (4,2), C (3,2) Z(A)=(5 4)+(8 1)=20+8=28Z(B)=(5 4)+(8 2)=20+16=36Z(C)=(5 3)+(8 2)=15+16=31 Minima is at (4,1)

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