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MHT CET202012 Oct 2020Morning ShiftMathematicsLinear ProgrammingActual

If Z =7 x+y subject to 5 x+y 5, x+y 3, x 0, y 0 , then minimum value of Z is

Options

  1. A2
  2. B5
  3. C6
  4. D3

Correct answer

B. 5

Step-by-step solution

Feasible area is shaded. Point of intersection of given lines is P ( 1 2 , 5 2 ) Co-ordinates of points are as follows : C (3,0) ; P ( 1 2 , 5 2 ) and B (0,5) We have Z=7 x+yZ_ (c) =21+0=21 Z_ (B) =0+5=5Z_ (P) = 7 2 + 5 2 =6 Thus minimum value is 5.

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