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AP EAMCET201724 Apr 2017Evening ShiftMathematicsApplication of DerivativesActual

Lagrange's mean value theorem is not applicable in [0,1] to the function

Options

  1. Af(x)= array l 1 2 -x, x < 1 2 ( 1 2 -x )^2, x 1 2 array .
  2. Bf(x)= array c x x , x 0 1, x=0 array .
  3. Cf(x)=x|x|
  4. Df(x)=|x|

Correct answer

A. f(x)= array l 1 2 -x, x < 1 2 ( 1 2 -x )^2, x 1 2 array .

Step-by-step solution

No solution. Refer to answer key.

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