MHT CET202122 Sep 2021Morning ShiftMathematicsMatricesActual
If A= [ array lll 1 & 0 & 1 0 & 2 & 3 1 & 2 & 1 array ] , then the value of determinant of A⁻¹ is
Options
- A-6
- B-1 6
- C1 36
- D36
Correct answer
B. -1 6
Step-by-step solution
aligned & We have A= [ array lll 1 & 0 & 1 0 & 2 & 3 1 & 2 & 1 array ] & |A|=(2-6)+(0-2)=-6 aligned We know that | A ⁻¹ |= 1 | ~A | | A ⁻¹ |= 1 -6