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MHT CET202613 April 2026Evening ShiftMathematicsPair of LinesActual

The pair of straight lines represented by the equation 3 x^2 - 4xy + 3 y^2 = 0 are

Options

  1. Acoincident.
  2. Bperpendicular.
  3. Cinclined at 30^ to each other.
  4. Dinclined at 60^ to each other.

Correct answer

C. inclined at 30^ to each other.

Step-by-step solution

Comparing the given equation 3 x^2 - 4xy + 3 y^2 = 0 with the general equation ax^2 + 2hxy + by^2 = 0 , we get: a = 3 , h = -2 , b = 3 The angle between the lines is given by: = | 2 h^2 - ab a + b | Substituting the values: = | 2 (-2)^2 - ( 3 )( 3 ) 3 + 3 | = | 2 4 - 3 2 3 | = 1 3 = 30^ Answer: inclined at 30^ to each other.

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