MHT CET202611 April 2026Morning ShiftMathematicsPair of LinesActual
If the equation x^2 - ky^2 - 4x + 6y - 5 = 0 represents a pair of straight lines, then their point of intersection is
Options
- A(1, 2)
- B(2, 3)
- C(3, 4)
- D(4, 5)
Correct answer
B. (2, 3)
Step-by-step solution
The given equation is x^2 - ky^2 - 4x + 6y - 5 = 0 . Comparing this with the general second-degree equation ax^2 + 2hxy + by^2 + 2gx + 2fy + c = 0 , we get: a = 1 , h = 0 , b = -k , g = -2 , f = 3 , c = -5 . For the equation to represent a pair of straight lines, the condition is abc + 2fgh - af^2 - bg^2 - ch^2 = 0 . Substituting the values: (1)(-k)(-5) + 0 - (1)(3)^2 - (-k)(-2)^2 - 0 = 0 5k - 9 + 4k = 0 9k = 9 k = 1 So, the equation of the pair of straight lines is x^2 - y^2 - 4x + 6y - 5 = 0 . Let F(x, y) = x^2 -