The equation of pair of lines y= p x and y= q x can be written as (y- p x)(y- q x)=0 . Then the equation of the pair of the angle bisectors of the lines x^2-4 x y-5 y^2=0 is

Step-by-step solution

Equation of angle bisector of two lines whose general equation is a x^2+2 ~h x y+b y^2=0 is x^2-y^2 a-b = x y h Comparing given equation x^2-4 x y-5 y^2=0 with a x^2+2 ~h x y+ b y^2=0 , we get a=1, b=-5, h=-2 Equation of angle bisectors is aligned & x^2-y^2 1-(-5) = x y -2 & x^2-y^2=-3 x y & x^2+3 x y-y^2=0 aligned