The joint equation of the lines pair of lines passing through the point (3,-2) and perpendicular to the lines 5 x^2+2 x y-3 y^2=0 is

Step-by-step solution

Joint equation of the liens passing through the point (x₁, y₁ ) and perpendicular to the lines ax ^2+2 ~h x y+ b y^2=0 is: aligned & a x^2+2 ~h x y+ b y^2=0 is: & b (x-x₁ )^2-2 ~h (x-x₁ ) (y-y₁ )+ a (y-y₁ )^2=0 aligned Equation of the required line is: array ll & Equation of the required line is: & -3(x-3)^2-2(x-3)(y+2)+5(y+2)^2=0 & -3 (x^2-6 x+9 )-2(x y+2 x-3 y-6) & +5 (y^2+4 y+4 )=0 array aligned & -3 x^2+18 x-27-2 x y-4 x+6 y+12+5 y^2 & +20 y+20=0 & 3 x^2+2 x y-5 y^2-14 x-26 y-5=0 aligned